loburch wrote:I am trying to determine how much mineral will be in a liter of water, and also how many milligrams of the mineral there are in a teaspoon.

The mineral has a density of 2.32 g/cm3 and the specific gravity is 1.724. I want to add 1 teaspoon of this mineral into 1 liter of water and need to know how many milligrams of mineral there will be in this liter, or how many ppm of the mineral there will be in the liter after I have added 1 teaspoon of the mineral.

I' feel like this

but look much better than that in real life

Thanks! Miss Lo

There is a bit of a conflict between "density of 2.32 g/cm3 and the specific gravity is 1.724." Specific gravity is nothing more than the ratio of something's density to water. Water at 4 Â°C is 1 g/cmÂ³. At 20 Â°C, it is a

tiny bit less, so there can be very minor differences based on temperature. You will need to sort out which is correct. Also there can be a difference between "block" density of a large piece and the bulk density of a ground-up powder.

When you figure out correct density, a teaspoon is 4.93 cmÂ³. Multiply density by that to get grams. If we assume density is based on the specific gravity, 1.724 g/cmÂ³, you'll have 8.5 g or 8500 mg in 1 L of water. 1L of water weighs 1 kg, so 8500 ppm by weight.

(BUT you need to straighten out density. This solution simply ASSUMES.)