landscape project

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landscape project

Postby Tammy » Tue Feb 17, 2004 8:44 pm

I have a retaining wall that is 9' high, 6' wide and 36' long. I'm using landscape timbers that are 8' long by 5" wide and 5" thick. How many timbers will I need
Tammy
 

Re: landscape project

Postby Knight » Wed Feb 18, 2004 2:22 am

Tammy wrote:I have a retaining wall that is 9' high, 6' wide and 36' long. I'm using landscape timbers that are 8' long by 5" wide and 5" thick. How many timbers will I need
A bit of confusion here Tammy... If your "wall" is 9' x 6' x 36', its not a wall, its a cube.

In any event, you timber dimesions are 8' by 0.416' x 0.416', so you can divide those dimensions into your area to get the number needed. I'm assuming that you can cut the timbers to length where they overlap, so I'd use somthing like this:

<based on a wall 9' by 36', ignoring the depth of the timber>

9'x36' = 324 Ft²

8'x0.416 = 3.33 Ft²

324 Ft²/3.33 Ft² = 97.35, or 98 Timbers
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Re: landscape project

Postby K^2 » Tue Mar 02, 2004 1:47 pm

Knight wrote:A bit of confusion here Tammy... If your "wall" is 9' x 6' x 36', its not a wall, its a cube.

Technicaly, it isn't a cube either.
K^2
 

Re: landscape project

Postby Knight » Tue Mar 02, 2004 9:25 pm

K^2 wrote:
Knight wrote:A bit of confusion here Tammy... If your "wall" is 9' x 6' x 36', its not a wall, its a cube.

Technicaly, it isn't a cube either.

Technically, it is...
Code: Select all
WordNet Dictionary
 
  Definition:   [n]  a block in the (approximate) shape of a cube
                [n]  any of several tropical American woody plants
                     of the genus Lonchocarpus whose roots are used
                     locally as a fish poison and commercially as a 
                     source of rotenone
                [n]  the product of three equal terms
                [n]  a three-dimensional shape with six square or
                     rectangular sides
                [n]  a hexahedron with six equal squares as faces
                [v]  raise to the third power
                [v]  cut into cubes; "cube the cheese"

See specifically definitions one, three, and four. Granted, I'd have been more correct to say that it was an irregular hexahedron, but I thought that this forum was for the discussion of conversion and its associated mathmatics, rather than precise etymology.
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