I have the answer to Part A, but need help on Part B. I showed you how I arrived at the answer for Part A.

Part A: A urine specimen collected over 12 hours has a volume of 900 mL and a sodium value of 90 mEq/L. What is the sodium result in terms of volume of collection? Answer:

90 mEq = x mEq

_______ ______ cross multiply

1000 mL 900 mL

81000 = 1000 x

_____ ______ divide by 1000

1000 1000

x= 81 mEq/900 mL

Part B: What is the urine sodium value in terms of mg of sodium per 12 hours?

I need a conversion factor for mEq to mg, and do I leave the 90 mEq/L in L or also conver that to mL?

Thank you, Brenda

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