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If a 5 lb block of ice fell from 30' how much force would it have on impact?

- jmpal

2012.1.8

F=Mass x Accel

free falling body, uniform acceleration (Newton's 2nd Law) F=mg (g = gravitational field strength)

So, from physics we can use the formula for constant acceleration: x - x0 = v0 * t + 1/2 a*t*t

velocity = v = sqrt(2gh)

time = t = sqrt(2h/g)

v= sqrt(2 x 32 ft/s/s x 30 ft) = 43.81 ft per sec

t= sqrt(2 x 30 / 32) = 1.369 sec

From these formulas, an object would take 1.37 seconds to fall 30 feet, and would be traveling 43.8 ft/s when it gets there.

F = 5 lbs x 43.8 ft/s = 219 pound-force (lbf)

F=Mass x Accel

free falling body, uniform acceleration (Newton's 2nd Law) F=mg (g = gravitational field strength)

So, from physics we can use the formula for constant acceleration: x - x0 = v0 * t + 1/2 a*t*t

velocity = v = sqrt(2gh)

time = t = sqrt(2h/g)

v= sqrt(2 x 32 ft/s/s x 30 ft) = 43.81 ft per sec

t= sqrt(2 x 30 / 32) = 1.369 sec

From these formulas, an object would take 1.37 seconds to fall 30 feet, and would be traveling 43.8 ft/s when it gets there.

F = 5 lbs x 43.8 ft/s = 219 pound-force (lbf)

- Guest

2 posts
• Page **1** of **1**