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Postby JB » Mon Mar 17, 2008 5:32 am

If i needed to store 5.2 acre foot of water how long, wide, deep of a basin would i need.


Postby Guest » Mon Mar 17, 2008 9:47 pm

JB wrote:If i needed to store 5.2 acre foot of water how long, wide, deep of a basin would i need.

You basically have to pick two dimensions and divide into total volume to get the third.

5.2 acres x 1 foot deep, or 0.52 acres by 10 foot deep, etc.

An acre is 43560 ft², so 5.2 acre-foot is 266512 ft³. How about a nice 66' x 66' x 52' rectangular solid? (Or any other three numbers with the same product, like 132' x 132' x 13')

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