1/27 part of a sylinders volum

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1/27 part of a sylinders volum

Postby Thomas » Thu Sep 01, 2005 12:15 am

I have made a model of a sylinder built to contain 1 litre of liquid. Now I have been asked to make another model of the same sylinder containing 1/27 part of the volume of the first sylinder. So far so good. But can someone please tell me why the length of the 1/27 sylinder gets correct in scale when divided with the number three (3)?

Hope some one can help me on this:-)


Postby Guest » Thu Sep 01, 2005 1:21 am

3^3 = 27, (1/3)^3 = 1/27

This matters because the volume of a cylinder is pi*h*r^2

if h and r are both divided by 3, the expression for volume will contain (1/3)^3

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