Could anybody please explain how to convert milli moles of bicarbonate into mg/l?
Any insight would be very much appreciated
Thanks in advance
N
Anonymous wrote:I can't create the minus sign superscript in text, but bicarbonate is the negative ion HCO3.
For any such calculation, the key is knowing the weight of a "mole" which is Avagadro's number of atoms, molecules, or ions. You have to add up the atomic weights of the constitutants and that number is a mass in grams of a mole.
Using rounded integer weights (you should use exact values from periodic table) it is about 1 + 12 + 3x16 = 61 atomic mass units, so about 61 g = 1 mole of HCO3. (61 ug = 1 umole) using u = 10^(-6) as I'm too lazy to fire up the character set to get a micro.