Could anybody please explain how to convert milli moles of bicarbonate into mg/l?

Any insight would be very much appreciated

Thanks in advance

N 8)

Dear convert-me.com forum visitors,

Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.

All the posts in the forum will be available and searchable. We understand there are a lot of useful information and we aren't going to remove anything. As for the new questions, you can always ask them on convert-me.com FaceBook page

Thank you for being with us and sorry for any inconveniences this could caused.

3 posts
• Page **1** of **1**

Could anybody please explain how to convert milli moles of bicarbonate into mg/l?

Any insight would be very much appreciated

Thanks in advance

N 8)

Any insight would be very much appreciated

Thanks in advance

N 8)

- Nick

I can't create the minus sign superscript in text, but bicarbonate is the negative ion HCO3.

For any such calculation, the key is knowing the weight of a "mole" which is Avagadro's number of atoms, molecules, or ions. You have to add up the atomic weights of the constitutants and that number is a mass in grams of a mole.

Using rounded integer weights (you should use exact values from periodic table) it is about 1 + 12 + 3x16 = 61 atomic mass units, so about 61 g = 1 mole of HCO3. (61 ug = 1 umole) using u = 10^(-6) as I'm too lazy to fire up the character set to get a micro.

For any such calculation, the key is knowing the weight of a "mole" which is Avagadro's number of atoms, molecules, or ions. You have to add up the atomic weights of the constitutants and that number is a mass in grams of a mole.

Using rounded integer weights (you should use exact values from periodic table) it is about 1 + 12 + 3x16 = 61 atomic mass units, so about 61 g = 1 mole of HCO3. (61 ug = 1 umole) using u = 10^(-6) as I'm too lazy to fire up the character set to get a micro.

- Guest

Anonymous wrote:I can't create the minus sign superscript in text, but bicarbonate is the negative ion HCO3.

For any such calculation, the key is knowing the weight of a "mole" which is Avagadro's number of atoms, molecules, or ions. You have to add up the atomic weights of the constitutants and that number is a mass in grams of a mole.

Using rounded integer weights (you should use exact values from periodic table) it is about 1 + 12 + 3x16 = 61 atomic mass units, so about 61 g = 1 mole of HCO3. (61 ug = 1 umole) using u = 10^(-6) as I'm too lazy to fire up the character set to get a micro.

Oops. I couldn't see your units. I thought you had ug. Well,

61 mg (approx) = 1 mmole, too.

- Guest

3 posts
• Page **1** of **1**