by Guest » Sun Sep 18, 2005 11:05 pm
For any triangle with sides a, b, and c
Let s = (a + b + c)/2
Then area A = SQRT(s*(s-a)*(s-b)*(s-c))
(Heron's formula)
For the special case a = b = c,
this reduces (aÂ²/4)*SQRT(3) or about 0.433*aÂ² where a is one of the equal sides.