by **Guest** » Thu Mar 31, 2005 6:42 pm

It's really an algebra problem, not a conversion problem. If the three dimensions are l, w, h, then:

1) l*w = 324

2) l*h = 135

3) w*h = 60

I was going to suggest solving the three equations for the three unknowns but just saw a simpler way.

If I multiply the three equations together, I get

l^2 x h^2 x w^2 = 324 x 135 x 60

The lefthand side is (l*w*h)^2 or volume squared,

so V = sqrt(324x135x60) = 1620 cu in.

If you need the dimensions as well as the volume, try variations of this:

Multiplying eqs 2 & 3

l*w*(h^2) = 135 x 60 but l*w = 324 so

324*(h^2) = 135 x 60 and you can solve for h.

Similar substitutions will give l and w.