poisenous gas

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poisenous gas

Postby arthurtyler » Mon Sep 17, 2007 1:30 pm

Can anyone help me? If a typical solvent such as Xylene is used in a paint it is then released into the atmosphere of the building. In this instance, the material (paint) is 52 % solids and 48% solvent. The total weight of the mixed material is 1,334 metric tonnes, which means 48% is 64 Tonnes of solvent.

My question is two part. Firstly, approximately how many cubic metres is 64 tonnes of solvent and more importantly, how many cubic metres of breathable air can it contaminate?

Just a rule of thumb is all I need.
arthurtyler
 

Re: poisenous gas

Postby Guest » Sun Sep 23, 2007 11:20 pm

arthurtyler wrote:Can anyone help me? If a typical solvent such as Xylene is used in a paint it is then released into the atmosphere of the building. In this instance, the material (paint) is 52 % solids and 48% solvent. The total weight of the mixed material is 1,334 metric tonnes, which means 48% is 64 Tonnes of solvent.

My question is two part. Firstly, approximately how many cubic metres is 64 tonnes of solvent and more importantly, how many cubic metres of breathable air can it contaminate?

Just a rule of thumb is all I need.


Some figure is wrong. If it is 1334 t, 48% is 640 t; however, if it 134 t, then 64 t is OK. I will answer for 64 ton.

1) For anything, Google MSDS and the chemical name for a materila safety data sheet. It will be full of facts you need to answer the question.

2) The specific gravity of xylene, as a LIQUID, is 0.87 (kg/L), so 64 t would be 73.6 m^3 of liquid.
3) You are really concerned after it evaporates, as a gas. One mole of any ideal gas occupies 22.4 L at 1 atm and 0 degrees C. (or 24.45 L at 25 degrees C). We will use that figure for moles of air.

4) The molecular weight of xylene is 106 g/mol, so you have 64 Mg x 1 mole/106 g = 603.8 kmol of xylene.

5) OSHA permits exposure of 100 ppm (mole fraction), so 1 mol of xylene mixed to 10000 moles of air would result in a mixture at limit. OSHA limits are stated at 25 degrees C.

6) You would contaminate 6.038 Gmol of air
occupying 147,6 billion liters or 147.6 x 10^ m^3 ( a cube 529 m on a side.) at the legal exposure limit. In a smaller space, you would be over the allowed exposure limit.
Guest
 


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