Conversions involving algebra

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Conversions involving algebra

Postby Symphonie » Mon Sep 13, 2004 8:19 am

Hello. I'm not completely sure how to do all of this yet because I'm currently learning this all over again in Physics before we start going into more advanced things. There are a few questions that I had on one of my worksheets that I wasn't too sure about with my answers. I was wondering what the answers were and what methods you use to get these answers. The questions are:

1) 70.5 cm^3 to mL (This one I didn't have any idea how to do.)

2) 8.22 x 10^-5 micrometers to Å (Å= 1x 10^-10 m)

3)9.92 x 10 ^7 mm to m

Any help is appreciated. Thanks in advance!
Symphonie
 
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Re: Conversions involving algebra

Postby Knight » Tue Sep 14, 2004 2:02 am

Symphonie wrote:Hello. I'm not completely sure how to do all of this yet because I'm currently learning this all over again in Physics before we start going into more advanced things. There are a few questions that I had on one of my worksheets that I wasn't too sure about with my answers. I was wondering what the answers were and what methods you use to get these answers. The questions are:

1) 70.5 cm^3 to mL (This one I didn't have any idea how to do.)

2) 8.22 x 10^-5 micrometers to Å (Å= 1x 10^-10 m)

3)9.92 x 10 ^7 mm to m

Any help is appreciated. Thanks in advance!

1) 70.5 ml.

Remember that the SI system defines one liter is the volume of 1,000 cubic centimeters. Therefore 1 cubic centimeter will be one milliliter.

2) 0.822 Å.

You need to remember to convert 8.22 x 10^-5 micrometers to meters, and then divide by 1x10^-10 m/Å.

(8.22 x 10^-5 µm) · (1 x 10^-6 m/µm) = 8.22 x 10^-11 m

8.22 x 10^-11 m / 1 x 10^-10 m/Å = 0.822 Å

3) 9.92 x 10^-10 m

There are 1 x 10^-3 mm/m, so:

(9.92 x 10^-7) · (1 x 10^-3) = 9.92 x 10^-10
William J. Knight
Health Physicist
Los Alamos National Labs
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