If you want to do these problems on your own, read

this page.

The acceleration due to gravity is 9.80665 m/sÂ² [down].

a) Since the elevator is descending at a constant rate, the acceleration is zero. The net force will be 588.399 N, and the scale will read 60 kg.

b) (m*a)+f_gravity = (60. kg * -2.0 m/sÂ²) + 588.399 N = 468.3993 N. Divide by acceleration due to gravity, therefore the scale will read approximately 47.8 kg.

c) This one is a little trickier. The elevator is ascending, but it is slowing down, so the acceleration is going in the opposite direction (downward). Since this acceleration (2.0 m/sÂ² [down]) is exactly the same as in the previous question, the scale will read the same (47.8 kg).

d) Acceleration is 2.0 m/sÂ² [up]. Use the same formula as in question b.

(m*a)+f_gravity/g = ((60. kg * 2.0 m/sÂ²) + 588.399 N)/9.80665 m/sÂ²) = approximately 72.2 kg.

I make no claims to the correctness of this advice. Use your own judgement to confirm this advice.