by Guest » Mon May 23, 2005 6:23 pm
Yes, that's enough. The density of any gas is
rho = MP/RT
M is the molecular weight, 28.02 u
P is the pressure, 1 atm is normal for "standard conditions"
T is the absolute temperature. 60 Â°F and 68 Â°F are the usual "standard" temperatures in english unit gas measure. We'll assume 68 Â°F and convert it to Rankine, 527.7 R.
R is the gas constant, in English units, is 0.7302 atm-ft^3/(lbmol-R)
rho = 28.02 lb/mol x 1 atm/ (0.7302 atm-ft^3/(lbmol-R) x 527.7 R) = 0.0727 lb/ft^3.
Then 20.2 lb/hr x 1hr/60 min x 1 ft^3/.0727 lbs = 4.63 ft^3/m. Since I used the pressure and temp. of standard conditions, those are scfm.